25^2=7^2+x^2

Solution for 25^2=7^2+x^2 equation:

25^2=7^2+x^2

We move all terms to the left:

25^2-(7^2+x^2)=0

We add all the numbers together, and all the variables

-(7^2+x^2)+625=0

We get rid of parentheses

-x^2+625-7^2=0

We add all the numbers together, and all the variables

-1x^2+576=0

a = -1; b = 0; c = +576;
Δ = b2-4ac
Δ = 02-4·(-1)·576
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-1}=\frac{-48}{-2}
=+24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-1}=\frac{48}{-2}
=-24
$